A 307Kb PDF of this article as it appeared in the magazine—complete with sketch—is available by clicking HERE
Given: parallelogram ABCD, AE bisector of angle BAD, AE & BC extended meet at F, Q is center of circle passing through points F, C, and E, angle BQD is 112°. What is angle QBD?
Dave Lindell, PS, retired after 36 1/2 years with the City of Los Angeles. He keeps surveying part BAD, AE & BC extended meet at F, Q is center of time to stay busy and keep out of trouble.
The solution can be found HERE
A 307Kb PDF of this article as it appeared in the magazine—complete with sketch—is available by clicking HERE